Tentukan Massa molekul relatif dari senyawa berikut
a) Cu(OH)2 (Ar Cu = 63,5 Ar O = 16 Ar H = 1)
b) (NH4)2SO4 (Ar N = 14 Ar S = 32)
a) Cu(OH)2 (Ar Cu = 63,5 Ar O = 16 Ar H = 1)
b) (NH4)2SO4 (Ar N = 14 Ar S = 32)
Jawaban:
97,5
152
Penjelasan:
Mr Cu(OH)2 = Ar Cu + (Ar O + Ar H) x 2
= 63,5 + (16 + 1) x 2
= 63,5 + 17 x 2
= 63,5 + 34
= 97,5
Mr (NH4)2SO4
= (Ar N + 4 Ar H) x 2 + Ar S + 4 Ar O
= (14 + 4 x 1) x 2 + 32 + 4 x 16
= (14 + 4) x 2 + 32 + 64
= (28)2 + 96
= 56 + 96
= 152
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mohon dicek lagi ya semoga membantu
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